19 2024-11-19  Dienstag Nachmittag
Anna Herzog - Alfred Kampel
   

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Paar: 19    Anna Herzog - Alfred Kampel

Score: 199,1 *    52,679 %    Platz: 6    
                        
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde    %      Ges        %        Name d. Gegners

 1     9    O-W   9     25   3T   N  = H10   110        9,0   64                                        Haberbauer - Smeikal
                        26   4P   N  = K10   620        8,0   57                                            
                        27   2K   W +2 HD       -130    8,0   57     25,0   60     25,0   59,524            

 2     1    O-W   1     4    3P   N  = HA    140        3,0   21                                        Kastner - Simkovics
                        5    3H   S  = KB    140        8,0   57                                            
                        6    3Nx  W -2 T6    500        0,0    0     11,0   26     36,0   42,857            

 3     2    O-W   2     10   5P   W -2 HB    200        4,0   29                                        Trilety - Bachmaier
                        11   2N   S  = T6    120        6,0   43                                            
                        12   3Kx  O -1 HA    100       10,0   71     20,0   48     56,0   44,444            

 4     3    O-W   3     16   4P   N -1 P7        -50   13,0   93                                        Mandt - Griensteidl
                        17   1N   S +1 HA    120        1,0    7                                            
                        18   3P   S -2 K3       -200   10,0   71     24,0   57     80,0   47,619            

 5     4    O-W   --    22                     Pause    7,4   53                                        Pause
                        23                     Pause    7,4   53                                            
                        24                     Pause    7,4   53     22,1   53    102,1   48,631            

 6     5    O-W   5     1    3N   S -1 T3        -50   11,0   79                                        Mayr - Soukop
                        2    1P   S -2 H10      -200   13,0   93                                            
                        3    2H   W +1 P7       -140    8,0   57     32,0   76    134,1   53,224            

 7     6    N-S   6     7    4H   O  = K10      -620    8,0   57                                        Hensler - Thorpe
                        8    2N   O  = TA       -120    6,0   43                                            
                        9    3H   N -1 TA        -50    0,0    0     14,0   33    148,1   50,383            

 8     7    N-S   7     13   2H   W -2 PD    200       14,0  100                                        Obojes - Ringdorfer
                        14   3P   S  = HA    140        4,0   29                                            
                        15   3Tx  O -3 H5    500       14,0  100     32,0   76    180,1   53,609            

 9     8    N-S   8     19   3T   S  = H10   110        8,0   57                                        Kadlec - Mocza
                        20   3N   W  = T5       -600   11,0   79                                            
                        21   1N   W -1 T3     50        0,0    0     19,0   45    199,1   52,679            


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