3 2020-06-22  Montag Nachmittag
Gerhard Schüller - Alexander Haltrich
   

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Paar: 3    Gerhard Schüller - Alexander Haltrich

Score: 81,0 *    50,0 %    Platz: 5    
                  
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %     Ges      %        Name d. Gegners

 1     2    O-W   6     4    4N  W -2 H5    200        1,0   17                                     Koril - Oviedo
                        5    2P  N -2 KB       -200    6,0  100                                             
                        6    2H  N +4 K7    230        6,0  100     13,0   72    13,0   72,2                

 2     4    N-S   5     25   2H  N +2 K9    170        0,0    0                                     Rathammer - Graf
                        26   4P  W -1 H4    100        6,0  100                                             
                        27   4H  W  = TA       -420    0,0    0      6,0   33    19,0   52,8                

 3     1    O-W   10    7    3N  N  = H9    600        5,0   83                                     Falchetto - Elchner
                        8    2P  S +2 H3    170        1,0   17                                             
                        9    3T  S +2 P4    150        4,0   67     10,0   56    29,0   53,7                

 4     3    N-S   --    16                    Pause    3,0   50                                     Pause   
                        17                    Pause    3,0   50                                             
                        18                    Pause    3,0   50      9,0   50    38,0   52,8                

 5     5    N-S   2     10   2N  N  = H3    120        4,0   67                                     Neumayr - Kadlec
                        11   4H  O -1 P10    50        2,0   33                                             
                        12   4P  W  = K4       -420    3,0   50      9,0   50    47,0   52,2                

 6     5    O-W   4     13   6H  O -1 PA    100        3,0   50                                     Soukop - Mayr
                        14   4K  N +1 P10   150        6,0  100                                             
                        15   2P  N  = TA    110        1,0   17     10,0   56    57,0   52,8                

 7     2    N-S   9     22   4P  O +1 K5       -650    1,0   17                                     Neuwirth - Mandt
                        23   3H  S +2 PA    200        1,0   17                                             
                        24   3N  N  = P5    400        3,0   50      5,0   28    62,0   49,2                

 8     3    O-W   7     1    3K  O -1 PA     50        2,0   33                                     Gareis - Streicher
                        2    5T  N  = KA    600        2,0   33                                             
                        3    6N  S -3 HA       -150    6,0  100     10,0   56    72,0   50,0                

 9     4    O-W   1     19   3T  W  = H3       -110    3,0   50                                     Horvath - Schreiber
                        20   3N  W  = KB       -600    6,0  100                                             
                        21   3N  N  = K2    600        0,0    0      9,0   50    81,0   50,0                


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