4 2020-02-04  Ö-Rallye CBC
Beatrix Hillebrand - Günter Eipeldauer
   

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Paar: 4    Beatrix Hillebrand - Günter Eipeldauer

Score: 77,6 *    47,9 %    Platz: 4    
                 
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %      Ges      %        Name d. Gegners

 1     4    O-W   2     22   3P  N  = K6    140        3,0   50                                      Hochstöger - Michl
                        23   4P  W  = P5       -620    2,0   33                                             
                        24   6P  O  = HB       -980    1,0   17      6,0   33      6,0   33,3               

 2     2    O-W   7     7    4Px W -2 HA    500        2,0   33                                      Sova - Musiol
                        8    6P  W -1 HK     50        0,0    0                                             
                        9    3N  S +3 H2    490        1,0   17      3,0   17      9,0   25,0               

 3     4    N-S   6     1    4P  S  = HA    420        4,0   67                                      Waneck - Cmyral
                        2    5K  O +1 P9       -420    6,0  100                                             
                        3    4P  N -1 KB        -50    4,0   67     14,0   78     23,0   42,6               

 4     1    O-W   10    10   3T  O  = PK       -110    6,0  100                                      Horvath - Nanevski-Nitsche
                        11   5P  W -1 TA     50        0,0    0                                             
                        12   4H  W  = P7       -420    3,0   50      9,0   50     32,0   44,4               

 5     3    N-S   9     19   4P  S  = KK    420        3,0   50                                      Simkovics - Falchetto
                        20   6N  O -1 K4    100        4,0   67                                             
                        21   4P  O +1 K10      -450    0,0    0      7,0   39     39,0   43,3               

 6     5    N-S   3     13   3H  N +1 P4    170        1,0   17                                      Pernkopf - Elchner
                        14   4P  N -2 HA       -100    4,0   67                                             
                        15   3P  O  = H4       -140    5,0   83     10,0   56     49,0   45,4               

 7     5    O-W   --    16                    Pause    2,9   48                                      Pause  
                        17                    Pause    2,9   48                                             
                        18                    Pause    2,9   48      8,6   48     57,6   45,7               

 8     2    N-S   1     25   3T  S +1 KA    130        5,0   83                                      Riedl - Pfingstner
                        26   2H  W  = K7       -110    6,0  100                                             
                        27   3N  N +1 H7    430        5,0   83     16,0   89     73,6   51,1               

 9     3    O-W   8     4    3T  O  = P8       -110    2,0   33                                      Zhou - Wieselmayer
                        5    5Px W -4 H9    800        0,0    0                                             
                        6    5Kx O -2 KD    500        2,0   33      4,0   22     77,6   47,9               


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