15 2015-10-08  Donnerstag Nachmittag
Imre Balogh - Maximilian Buchmayr
   

Ergebnisliste  <<  >>  1  2  3  4  5  6  7  11  12  13  14  15  16

Paar: 15    Imre Balogh - Maximilian Buchmayr

Score: 168,0    60,0 %    Platz: 2    
                      
Rnd  Tisch  Als  Geg  Board  Kont     Aus  Ergebnis  Score    %    Runde    %      Ges      %        Name d. Gegners

 1     5    O-W   5     17   4H  W  = HA       -420    8,0   80                                      Calvi - Blum
                        18   3N  O -2 H10   100        0,0    0                                             
                        19   3P  S -2 TA       -100    9,0   90                                             
                        20   4H  S +1 PD    650        2,0   20     19,0   48     19,0   47,5               

 2     6    O-W   6     25   3N  O -1 K7    100        7,0   70                                      Summer - Korbel
                        26   4P  S +1 K7    650        9,0   90                                             
                        27   3N  O +1 H7       -430   10,0  100                                             
                        28   2N  O  = T7       -120    7,0   70     33,0   83     52,0   65,0               

 3     7    O-W   7     5    5K  O -2 H3    100        3,0   30                                      Schreiber - Horvath
                        6    3N  O -1 T8    100        5,0   50                                             
                        7    2P  O +1 K9       -140    3,0   30                                             
                        8    3N  S +2 K5    460        0,0    0     11,0   28     63,0   52,5               

 4     1    O-W   1     13   4P  O  = T8       -620    3,0   30                                      Breitenfeld - Tluchor
                        14   3N  W  = PD       -400    8,0   80                                             
                        15   3P  S -1 TK       -100    9,0   90                                             
                        16   3P  O  = KA       -140    8,0   80     28,0   70     91,0   56,9               

 5     2    O-W   2     21   1N  O +1 H4       -120    6,0   60                                      Strahoda - Pokorny
                        22   3N  W +1 P3       -630    6,0   60                                             
                        23   3N  O +2 K2       -660    9,0   90                                             
                        24   1K  W  = T5        -70    8,0   80     29,0   73    120,0   60,0               

 6     3    N-S   3     1    4P  O  = T2       -420    5,0   50                                      Sommeregger - Leifer
                        2    5T  N +1 KA    620        8,0   80                                             
                        3    2P  N +2 K2    170        8,0   80                                             
                        4    5P  O -2 H2    200        5,0   50     26,0   65    146,0   60,8               

 7     4    N-S   4     9    3H  N -2 K2       -100    6,0   60                                      Hovis - Lindenlauf
                        10   3N  S +2 P2    660        6,0   60                                             
                        11   3H  S -1 KA        -50    4,0   40                                             
                        12   1N  O +1 P2       -120    6,0   60     22,0   55    168,0   60,0               


Ergebnisliste  <<  >>  1  2  3  4  5  6  7  11  12  13  14  15  16