12 2015-05-04  Ö-Rallye
Dagmar Bader - Herbert Prichzi
   

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Paar: 12    Dagmar Bader - Herbert Prichzi

Score: 154,4    40,8 %    Platz: 15    
                        
Rnd  Tisch  Als  Geg  Board  Kont      Aus  Ergebnis  Score    %    Runde    %      Ges      %        Name d. Gegners

 1     2    O-W   2     4    5N   W +2 P8       -720    5,0   36                                      Leifer - Leifer
                        5    4P   W -3 HA    150        1,0    7                                            
                        6    3N   W +1 KK       -630   10,0   71     16,0   38     16,0   38,1              

 2     3    O-W   3     10   Pass              0        6,0   43                                      Kaltenberger - Winkler
                        11   3N   W -4 P3    200        0,0    0                                            
                        12   3K   O -2 T6    100        4,0   29     10,0   24     26,0   31,0              

 3     4    O-W   4     16   4H   W -2 T4    200        6,0   43                                      Griensteidl - Griensteidl
                        17   4H   N -1 T5        -50   11,0   79                                            
                        18   4P   S  = K8    620        1,0    7     18,0   43     44,0   34,9              

 4     5    O-W   5     22   4P   S  = T10   420        4,0   29                                      Bittmann - Falchetto
                        23   5K   W -6 PA    600        8,0   57                                            
                        24   4P   N -1 HA        -50    4,0   29     16,0   38     60,0   35,7              

 5     6    O-W   6     1                         A+    8,4   60                                      Ahluwalia - Polletin
                        2    4P   S -1 H3       -100   14,0  100                                            
                        3    3H   O  = K3       -140    6,0   43     28,4   68     88,4   42,1              

 6     7    O-W   7     7    3N   S +1 P4    630        1,0    7                                      Mandt - Hensler
                        8    3N   N -1 H3        -50    8,0   57                                            
                        9    3H   O -4 KA    400        1,0    7     10,0   24     98,4   39,0              

 7     8    N-S   8     13   3N   N +1 HB    630        5,0   36                                      Bamberger - Weixlbraun
                        14   3H   S  = P2    140        0,0    0                                            
                        15   3N   O -3 H2    150       14,0  100     19,0   45    117,4   39,9              

 8     9    N-S   9     19   3P   N -2 H10      -100    6,0   43                                      Krones - Paesold
                        20   4Hx  N -5 P6      -1400    0,0    0                                            
                        21   3Px  S -2 K5       -500    0,0    0      6,0   14    123,4   36,7              

 9     1    N-S   1     25   3N   N +2 T10   460       11,0   79                                      Svanda - Svanda
                        26   1N   W  = H3        -90    6,0   43                                            
                        27   3Kx  O -3 HA    500       14,0  100     31,0   74    154,4   40,8              


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